Cyclic permutations
9 September 2007 – 5:09 pm by wgTake the number 142,857. Multiply it by 2, 3, 4, 5, 6, and 7, as follows:
142,857 * 1
142,857 * 2
142,857 * 3
142,857 * 4
142,857 * 5
142,857 * 6
142,857 * 7
Well I thought it was neat anyway 
